# Line slope calculator 7x+4y=40

**Straight line given by points A[0; 10] and B[4; 3]**

## Calculation:

**Slope-intercept form of line:**y = -1.75x+10

**Canonical form of the line equation:**7x+4y-40 = 0

**Parametric form of the line equation:**

x = 4t

y = -7t+10 ; t ∈ R

**Slope:**m = -1.75

**Slope angle of line: φ =**-60°15'18″ = -1.0517 rad

**X intercept:**x

_{0}= 5.7143

**Y intercept:**y

_{0}= q = 10

**Distance line from the origin:**d

_{0}= 4.9614

**The length of the segment AB: |AB| =**8.0623

**Vector: AB =**(4; -7)

**Normal vector: n =**(7; 4)

**Midpoint of the segment AB: M =**[2; 6.5]

**Perpendicular Bisector equation:**4x-7y+37.5 = 0

**Vector OA = (0; 10) ; |OA| = 10**

**Vector OB = (4; 3) ; |OB| = 5**

**Scalar product OA .OB = 30**

**Angle ∠ AOB = 53°7'48″ = 0.9273 rad**